Theorems

(Difference between revisions)

Revision as of 22:51, 18 October 2009

$d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

Example: Find the distance between point A(5,-7) and B(-6,-2) and leave your answer in radical form.

Solution: Let A be point 1 and B be point 2. We have $x_1\ =5,y_1 = -7, x_2 = -6, y_2 = -2$

Substituting we have $d=\sqrt{(\ -6 -5)^2 + (-2 - -7)^2} = \sqrt{(\ -11)^2 + (-2 +7)^2} = \sqrt{(\ -11)^2 + (+5)^2} =$

Example: Given two sides of a triangle are 8 inches and 11 inches, find all the possible lengths of the third side (also known as $S 3$ )

Solution: We know that 8 + 11 must be greater than S_3

@@ Line 7: / Line 7: @@
 Solution: Let A be point 1 and B be point 2. We have <math>x_1\ =5,y_1 = -7, x_2 = -6, y_2 = -2</math>
-Substituting we have <math>d=\sqrt{(\ -6 -5)^2 + (-2 - -7)^2}</math>
+Substituting we have <math>d=\sqrt{(\ -6 -5)^2 + (-2 - -7)^2} =
+\sqrt{(\ -11)^2 + (-2 +7)^2} =
+\sqrt{(\ -11)^2 + (+5)^2} =
+</math>
 [[Media:Distance_&_Midpoint-9-2_ME.pdf‎|Distance & Midpoint 9-2 ME Worksheet]]